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Modsoft is a company founded by software developers,. The best answer to each one of our customer`s requests is nothing but a software product. .Q:

How to do a std::ostream_iterator in a loop to generate a string?

I’m new to C++ and I know I can do something like:
std::ostream_iterator strIter{“Hello”};
std::ostream_iterator strIter2{“World”};

std::copy(strIter,strIter2,std::ostream_iterator(cout, ”
“));

However, is there a way to generate strIter and strIter2 in a loop (just one by one like a For loop) to make it look like (or to be more precise) something like this:
for(std::string strIter; “Hello”!= ”
“; ++strIter)
{
std::ostream_iterator strIter;
std::ostream_iterator strIter2{“World”};
std::copy(strIter,strIter2,std::ostream_iterator(cout, ”
“));
}

Is that a good approach?

A:

You should prefer
std::copy(std::begin(s), std::end(s), std::ostream_iterator(cout, ”
“));

The reason is that you don’t need the loop at all: begin() and end() return iterators to the first and the last elements, and std::copy() will work for the range they return.
If the range is from the first to the nth element and you want to use a single loop, you can use std::advance() to step over any unprocessed data:
for (std::ostream_iterator s(std::cout);

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